Optimal. Leaf size=84 \[ -\frac {2^{\frac {1}{2}+m} a^2 c \cos ^3(e+f x) \, _2F_1\left (\frac {3}{2},\frac {1}{2}-m;\frac {5}{2};\frac {1}{2} (1-\sin (e+f x))\right ) (1+\sin (e+f x))^{\frac {1}{2}-m} (a+a \sin (e+f x))^{-2+m}}{3 f} \]
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Rubi [A]
time = 0.08, antiderivative size = 84, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {2815, 2768, 72,
71} \begin {gather*} -\frac {a^2 c 2^{m+\frac {1}{2}} \cos ^3(e+f x) (\sin (e+f x)+1)^{\frac {1}{2}-m} (a \sin (e+f x)+a)^{m-2} \, _2F_1\left (\frac {3}{2},\frac {1}{2}-m;\frac {5}{2};\frac {1}{2} (1-\sin (e+f x))\right )}{3 f} \end {gather*}
Antiderivative was successfully verified.
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Rule 71
Rule 72
Rule 2768
Rule 2815
Rubi steps
\begin {align*} \int (a+a \sin (e+f x))^m (c-c \sin (e+f x)) \, dx &=(a c) \int \cos ^2(e+f x) (a+a \sin (e+f x))^{-1+m} \, dx\\ &=\frac {\left (a^3 c \cos ^3(e+f x)\right ) \text {Subst}\left (\int \sqrt {a-a x} (a+a x)^{-\frac {1}{2}+m} \, dx,x,\sin (e+f x)\right )}{f (a-a \sin (e+f x))^{3/2} (a+a \sin (e+f x))^{3/2}}\\ &=\frac {\left (2^{-\frac {1}{2}+m} a^3 c \cos ^3(e+f x) (a+a \sin (e+f x))^{-2+m} \left (\frac {a+a \sin (e+f x)}{a}\right )^{\frac {1}{2}-m}\right ) \text {Subst}\left (\int \left (\frac {1}{2}+\frac {x}{2}\right )^{-\frac {1}{2}+m} \sqrt {a-a x} \, dx,x,\sin (e+f x)\right )}{f (a-a \sin (e+f x))^{3/2}}\\ &=-\frac {2^{\frac {1}{2}+m} a^2 c \cos ^3(e+f x) \, _2F_1\left (\frac {3}{2},\frac {1}{2}-m;\frac {5}{2};\frac {1}{2} (1-\sin (e+f x))\right ) (1+\sin (e+f x))^{\frac {1}{2}-m} (a+a \sin (e+f x))^{-2+m}}{3 f}\\ \end {align*}
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Mathematica [C] Result contains complex when optimal does not.
time = 1.08, size = 285, normalized size = 3.39 \begin {gather*} -\frac {i 2^{-1-2 m} c e^{-i (e+f x)} \left (1+i e^{-i (e+f x)}\right )^{-2 m} \left (-(-1)^{3/4} e^{-\frac {1}{2} i (e+f x)} \left (i+e^{i (e+f x)}\right )\right )^{2 m} \left (e^{2 i (e+f x)} (-1+m) m \, _2F_1\left (-1-m,-2 m;-m;-i e^{-i (e+f x)}\right )+(1+m) \left (m \, _2F_1\left (1-m,-2 m;2-m;-i e^{-i (e+f x)}\right )-2 e^{i (e+f x)} (-1+m) \, _2F_1\left (-2 m,-m;1-m;-i e^{-i (e+f x)}\right )\right )\right ) (-1+\sin (e+f x)) (a (1+\sin (e+f x)))^m \sin ^{-2 m}\left (\frac {1}{4} (2 e+\pi +2 f x)\right )}{f (-1+m) m (1+m) \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )^2} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 0.21, size = 0, normalized size = 0.00 \[\int \left (a +a \sin \left (f x +e \right )\right )^{m} \left (c -c \sin \left (f x +e \right )\right )\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - c \left (\int \left (a \sin {\left (e + f x \right )} + a\right )^{m} \sin {\left (e + f x \right )}\, dx + \int \left (- \left (a \sin {\left (e + f x \right )} + a\right )^{m}\right )\, dx\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int {\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (c-c\,\sin \left (e+f\,x\right )\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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